题目描述
给一个链表,若其中包含环,请找出该链表的环的入口结点,否则,输出null。
思路:快慢针,当快针A与慢针B相遇时,在头结点出发一个慢针C,慢针B、C一起走,相遇时即为环的入口
function EntryNodeOfLoop(pHead){// write code hereif(pHead == null){return 1;}if(pHead.next == null){return null;}var fast = pHead;var slow = pHead;while(slow != null && fast.next != null){slow = slow.next;fast = fast.next.next;if(fast == slow) break;}var p1 = slow;var p2 = pHead;while(p1 != p2){p1 = p1.next;p2 = p2.next;}return p1;}